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If four dice are rolled, find the number of possible outcomes in which atleast one die shows 2.

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प्रश्न

If four dice are rolled, find the number of possible outcomes in which atleast one die shows 2.

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उत्तर

When a die is rolled number of possible outcomes is selecting an event from 6 events = 6C1

When four dice are rolled number of possible outcomes = 6C1 × 6C1 × 6C1 × 6C1

When a die is rolled number of possible outcomes in which ‘2’ does not appear is selecting an event from 5 events = 5C1

When four dice are rolled number of possible outcomes in which 2 does not appear = 5C1 × 5C1 × 5C1 × 5C1

Therefore the number of possible outcomes in which atleast one die shows 2

6C1 × 6C1 × 6C1 × 6C1 – 5C1 × 5C1 × 5C1 × 5C1

= 6 × 6 × 6 × 6 – 5 × 5 × 5 × 5

= 1296 – 625

= 671

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अध्याय 2: Algebra - Exercise 2.4 [पृष्ठ ३८]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
अध्याय 2 Algebra
Exercise 2.4 | Q 6 | पृष्ठ ३८
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