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If f : R → R is defined by f(x) = 3x − 5, prove that f is a bijection and find its inverse - Mathematics

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प्रश्न

If f : R → R is defined by f(x) = 3x − 5, prove that f is a bijection and find its inverse

योग
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उत्तर

Given f(x) = 3x – 5

Let y = 3x – 5

y + 5 = 3x

⇒ `(y + 5)/3` = x

Let g(y) = `(y + 5)/3`

gof(x) = g(f(x))

= g(3x – 5)

= `(3x - 5 + 5)/3`

= `(3x)/5`

= x

gof(x) = x

fog(y) = f(g(y))

= `f((y + 5)/3)`

= `3((y + 5)/3) - 5`

= y + 5 – 5

fog(y) = y

∴ gof = Ix and fog = IY

Hence f and g are bijections and inverses to each other.

Hence f is a bijection and f-1(y) = `(y + 5)/3`

Replacing y by x we get f-1(x) = `(x + 5)/3`

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अध्याय 1: Sets, Relations and Functions - Exercise 1.3 [पृष्ठ ३८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 1 Sets, Relations and Functions
Exercise 1.3 | Q 12 | पृष्ठ ३८

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