Question

If ∆ABC ~ ∆DEF such that area of ∆ABC is 16cm² and the area of ∆DEF is 25cm² and BC = 2.3 cm. Find the length of EF.

Triangles ABC and DEF are similar If area (∆ABC) = 16cm², area (∆DEF) = 25 cm² and BC = 2.3 cm, find EF.

Answer 1

We have,

`(Area(DeltaABC))/(Area(DeltaDEF))=(BC)^2/(EF)^2`

`\Rightarrow \frac{16}{25}=((2.3)^2)/(EF^2)`

`\Rightarrow EF=\sqrt{8.265}=2.875cm`