Advertisements
Advertisements
प्रश्न
If a2 + b2 = 74 and ab = 35, then find a + b.
Advertisements
उत्तर
Given, a2 + b2 = 74 and ab = 35
Since, (a + b)2 = a2 + b2 + 2ab ...[Using the identity, (a + b)2 = a2 + b2 + 2ab]
∴ (a + b)2 = 74 + 2 × 35
⇒ (a + b)2 = 144
⇒ `a + b = sqrt(144)` ...[Taking square root]
⇒ a + b = 12 ...[Rejecting – ve sign]
APPEARS IN
संबंधित प्रश्न
Use a suitable identity to get the following products.
`(3a - 1/2)(3a - 1/2)`
Using identities, evaluate 1022
Using identities, evaluate 297 × 303
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 104
Expand `("x"+1/2)^2`
Use the formula to find the value.
502 × 498
Expand:
(2a – 3b)2
The difference of the squares of two consecutive numbers is their sum.
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`9x^2 + 2xy + y^2/9`
Factorise the following.
18 + 11x + x2
