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प्रश्न
If A = `[(1, 3),(3, 4)]`, B = `[(-2, 1),(-3, 2)]` and A2 – 5B2 = 5C. Find matrix C where C is a 2 by 2 matrix.
योग
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उत्तर
Given: A = `[(1, 3),(3, 4)]`, B = `[(-2, 1),(-3, 2)]` and A2 – 5B2 = 5C
Now, A2 = A × A
= `[(1, 3),(3, 4)] xx [(1, 3),(3, 4)]`
= `[(1 xx 1 + 3 xx 3, 1 xx 3 + 3 xx 4),(3 xx 1 + 4 xx 3, 3 xx 3 + 4 xx 4)]`
= `[(1 + 9, 3 + 12),(3 + 12, 9 + 16)]`
= `[(10, 15),(15, 25)]`
And B2 = B × B
= `[(-2, 1),(-3, 2)] xx [(-2, 1),(-3, 2)]`
= `[(-2 xx (-2) + 1 xx (-3), -2 xx 1 + 1 xx 2),(-3 xx (-2) + 2 xx (-3), -3 xx 1 + 2 xx 2)]`
= `[(4 - 3, -2 + 2),(6 - 6, -3 + 4)]`
= `[(1, 0),(0, 1)]`
Now, A2 – 5B2 = `[(10, 15),(15, 25)] - 5[(1, 0),(0, 1)]`
= `[(10, 15),(15, 25)] - [(5, 0),(0, 5)]`
= `[(5, 15),(15, 20)]`
= `5[(1, 3),(3, 4)]`
= 5C
Hence, C = `[(1, 3),(3, 4)]`
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