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प्रश्न
If 10125 J of heat energy boils off 4.5 g of water at 100°C to steam at 100°C, find the specific latent heat of steam.
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उत्तर
Q = 10125 J
m = 4.5 g
Q = m x L
10125 = 4.5 x L
L = `10125/4.5` = 2250 J/G
Specific latent heat of steam is 2250 J/g
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