Question

How much charge in terms of Faraday is required for the reduction of 1 mol of Cu²⁺ to Cu?

Answer 1

The reduction of one mole of Cu²⁺ to Cu can be represented as:

\[\ce{Cu^{2+} + 2e^- -> Cu}\]

Since, in this reaction, there are two moles of electrons involved, the amount of charge required is 2F.