Question

How much Is Calcium oxide formed when 82g of calcium nitrate is heated? Also, find the volume of nitrogen dioxide evolved :

2Ca(NO₃)₂ → 2CaO+4NO₂+O₂

_{(Ca = 40 , N = 14,O = 16)}

Answer 1

2Ca(Na₃)₂ → 2CaO + 4NO₂ ↑ + O₂

At STP, 1 mole of any gas contains 22.4L

Since, 4 moles of NO are produced,

∴ volume of nitrogen dioxide obtained = 4 x 22.4 = 89.6 L

2 moles of Ca(NO₃)₂ produces 2 moles of CaO

328 g Ca(NO₃)₂ produces = 112 g CaO

1 g Ca(NO₃)₂ will produce = `112/328` g CaO

= 0.34 g CaO

Hence, 82 g of Ca(NO₃)₂ will produce = 82 x 0.34 = 27.88 g of CaO.