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प्रश्न
How do you prepare:
Actinoid elements show wide range of oxidation states.
Account for the following:
Actinoid elements show wide range of oxidation states.
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उत्तर
Actinides exhibit larger oxidation states because of the very small energy gap between 5f, 6d and 7s sub-shells. The energies are calculated on the basis of the (n + l) rule. The (n + l) values of the three orbitals are:
5f = 5 + 3 = 8
6d = 6 + 2 = 8
7s = 7 + 0 = 7
Since all the values are almost the same, therefore all orbitals can be involved in bonding resulting in a larger oxidation number for actinoids.
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संबंधित प्रश्न
Why do actinoids show a wide range of oxidation states?
Compare the chemistry of the actinoids with that of lanthanoids with reference to oxidation states
How would you account the following :
Highest fluoride of Mn is MnF4 whereas the highest oxide is Mn2O7.
Give reasons for the following:
The chemistry of actinoids elements is not so smooth as that of the lanthanoids.
Actinoid series begins at ____________ and ends at ____________.
The number of unpaired f-electrons in ytterbium (Z = 70) is ____________.
The electronic configuration of Ux+ ion is [Rn]. What is the value of x?
[At. No. of U = 92]
Which of the following properties is NOT of actinoids?
Maximum oxidation state exhibited by Chlorine is ______.
The incorrect statement among the following is:
