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प्रश्न
Given below is the number of units of electricity consumed in a week in a certain locality:
| Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 200 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
Calculate the median.
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उत्तर
| Class | Frequency (f) | Cumulative Frequency (cf) |
| 65- 85 | 4 | 4 |
| 85 – 105 | 5 | 9 |
| 105 – 125 | 13 | 22 |
| 125 – 145 | 20 | 42 |
| 145 – 165 | 14 | 56 |
| 165 – 185 | 7 | 63 |
| 185 – 205 | 4 | 67 |
| N = Σ𝑓 = 67 |
Now, N = 67
`⇒ N/2` = 33.5.
The cumulative frequency just greater than 33.5 is 42 and the corresponding class is 125 - 145.
Thus, the median class is 125 – 145.
∴ l = 125, h = 20, f = 20, cf = c.f. of preceding class = 22 and `N/2` = 33.5.
Now,
Median, `M = l + {h×((N/2−cf)/f)}`
`= 125 + {20 × ((33.5 − 22)/20)}`
= 125 + 11.5
= 136.5
Hence, the median = 136.5.
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