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From a Pack of 52 Cards, 4 Are Drawn One by One Without Replacement. Find the Probability that All Are Aces(Or Kings). - Mathematics

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प्रश्न

From a pack of 52 cards, 4 are drawn one by one without replacement. Find the probability that all are aces(or kings).

 
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उत्तर

Consider the given events.
A = An ace in the first draw
B = An ace in the second draw
C = An ace in the third draw
D = An ace in the fourth draw

\[\text{ Now } , \]

\[P\left( A \right) = \frac{4}{52} = \frac{1}{13}\]

\[P\left( B/A \right) = \frac{3}{51} = \frac{1}{17}\]

\[P\left( C/A \cap B \right) = \frac{2}{50} = \frac{1}{25}\]

\[P\left( D/A \cap B \cap C \right) = \frac{1}{49}\]

\[ \therefore \text{ Required probability }  = P\left( A \cap B \cap C \cap D \right) = P\left( A \right) \times P\left( B/A \right) \times P\left( C/A \cap B \right) \times P\left( D/A \cap B \cap C \right)\]

\[ = \frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} \times \frac{1}{49}\]

\[ = \frac{1}{270725}\]

In case of kings, the required probablity will be = \[\frac{1}{270725}\]

 
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Problems based on Probability
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 31: Probability - Exercise 31.2 [पृष्ठ २२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 31 Probability
Exercise 31.2 | Q 2 | पृष्ठ २२
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