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For the following equations, determine its order, degree (if exists) dddd(d2ydx2)3=1+(dydx) - Mathematics

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प्रश्न

For the following equations, determine its order, degree (if exists)

`(("d"^2y)/("d"x^2))^3 = sqrt(1 + (("d"y)/("d"x)))`

योग
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उत्तर

`(("d"^2y)/("d"x^2))^3 = sqrt(1 + (("d"y)/("d"x)))`

On squaring both sides, we get

`(("d"^2y)/("d"x^2))^(3 xx 2) = 1 + (("d"y)/("d"x))`

`(("d"^2y)/("d"x^2))^6 = 1 + ("d"y)/("d"x)`

In this equation

The highest order derivative is `("d"^2y)/("d"x^2)` and its power is 6.

∴ Its order = 2 and degree = 6

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Differential Equation, Order, and Degree
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Ordinary Differential Equations - Exercise 10.1 [पृष्ठ १४८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 10 Ordinary Differential Equations
Exercise 10.1 | Q 1. (vii) | पृष्ठ १४८
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