हिंदी

Find the zeroes of the quadratic polynomial 2x^2 – 11x + 15 and verify the relation between the zeroes and the coefficients.

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प्रश्न

Find the zeroes of the quadratic polynomial 2x2 – 11x + 15 and verify the relation between the zeroes and the coefficients.

Find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficients:

2x2 – 11x + 15

योग
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उत्तर

f(x) = 2x2 – 11x + 15

= 2x2 – (6x + 5x) + 15

= 2x2 – 6x – 5x + 15

= 2x(x – 3) – 5(x – 3)

= (2x – 5) (x – 3)

∴ f(x) = 0 ⇒ (2x – 5) (x – 3) = 0

⇒ 2x – 5 = 0 or x – 3 = 0 

⇒ `x = 5/2` or x = 3 

So, the zeroes of f(x) are `5/2` and 3. 

Sum of zeroes = `5/2 + 3`

= `(5 + 6)/2`

= `11/2`

= `(-("Coefficient of x"))/(("Coefficient of"  x^2))` 

Product of zeroes = `5/2 xx 3`

= `(-15)/2`

= `("Constant term")/(("Coefficient of"  x^2))`

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अध्याय 2: Polynomials - EXERCISE 2A [पृष्ठ ५२]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 2 Polynomials
EXERCISE 2A | Q 7. | पृष्ठ ५२
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