Question

Find the values of the following polynomials at a = –2 and b = 3:

a³ + 3a²b + 3ab² + b³

Answer 1

Given, a = –2 and b = 3

So, putting a = –2 and b = 3 in the given expressions, we get 

a³ + 3a²b + 3ab² + b³ = (–2)³ + 3(–2)²(3) + 3(–2)(3)² + (3)³

= –8 + 36 – 54 + 27

= 1