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प्रश्न
Find the value(s) of k so that PQ will be parallel to RS. Given : P(3, −1), Q(7, 11), R(−1, −1) and S(1, k)
योग
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उत्तर
Since, PQ || RS,
Slope of PQ = Slope of RS
Slope of PQ = `(11 + 1)/(7 - 3) = 12/4 = 3`
Slope of RS = `(k + 1)/(1 + 1) = (k + 1)/2`
∴ `3 = (k + 1)/2`
k + 1 = 6
k = 5
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