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प्रश्न
Find the value of ‘x’ in the given figure
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उत्तर
Given ∠DCB = 100° and ∠DBA = 128°
In the given figure
∠CBD + ∠DBA = 180°
∠CBD + 128° = 180°
∠CBD = 52°
Now exterior angle x = Sum of interior opposite angles.
x = ∠DCB + ∠CBD
= 100° + 52°
= 152°
x = 152°
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