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प्रश्न
Find the value of x in the following figure, where O is the centre of the circle:

योग
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उत्तर
Use the central angle
The given 160° O is the central angle ∠AOC.
A central angle equals the measure of the arc it subtends, so
AC = 160°
Find ∠ADC
∠ADC is an inscribed angle standing on arc AC.
For an inscribed angle:
inscribed angle = `1/2` × (intercepted arc)
x = ∠ADC = `1/2`AC
= `1/2`(160°)
= 80°
Quadrilateral ABCD is cyclic (all vertices on the circle), so opposite angles are supplementary:
∠ABC + ∠ADC = 180°.
At B, x is the exterior angle between the tangent and chord BC.
This exterior angle is supplementary to the interior angle ∠ABC
x = 180° − ∠ABC.
From the cyclic quadrilateral relation,
180° − ∠ABC = ∠ADC.
x = ∠ADC = 80°.
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Circles - Exercise 15A [पृष्ठ ३२९]
