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Find the value of the following expression: sin 45° cos 30° – cos 45° sin 30° - Mathematics

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प्रश्न

Find the value of the following expression:

sin 45° cos 30° – cos 45° sin 30°

योग
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उत्तर

Given: sin 45° cos 30° – cos 45° sin 30°

Step-wise calculation:

1. Use the sine difference identity:

sin (A – B) = sin A cos B – cos A sin B

So, the expression equals sin (45° – 30°) = sin 15°.

2. Compute sin 15° by substituting standard values:

`sin 45^circ = sqrt(2)/2` 

`cos 30^circ = sqrt(3)/2`

`cos 45^circ = sqrt(2)/2` 

`sin 30^circ = 1/2` 

So, sin 45° cos 30° – cos 45° sin 30°

= `(sqrt(2)/2) (sqrt(3)/2) - (sqrt(2)/2) (1/2)`

= `(sqrt(2)/2) xx ((sqrt(3) - 1)/2)` 

= `(sqrt(2) (sqrt(3) - 1))/4` 

= `((sqrt(6) - sqrt(2)))/4`

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अध्याय 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18A [पृष्ठ ३७२]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 18 Trigonometric Ratios of Some Standard Angles and Complementary Angles
Exercise 18A | Q 3. | पृष्ठ ३७२
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