Advertisements
Advertisements
प्रश्न
Find the value of the following:
`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`
Advertisements
उत्तर
`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`
= `cot theta/cot theta + (sin theta* tan theta xx "cosec" theta)/(cos theta xx tan theta * sec theta)`
= `1 + sin theta/cos theta xx 1/sintheta xx costheta/1`
= 1 + 1
= 2
APPEARS IN
संबंधित प्रश्न
If sin θ =3/5, where θ is an acute angle, find the value of cos θ.
If tan A = cot B, prove that A + B = 90°.
Evaluate:
14 sin 30° + 6 cos 60° – 5 tan 45°
Find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° – 3A) . cosec 42° = 1
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
If \[\tan A = \frac{5}{12}\] \[\tan A = \frac{5}{12}\] find the value of (sin A + cos A) sec A.
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
If tan2 45° − cos2 30° = x sin 45° cos 45°, then x =
The value of cosec(70° + θ) – sec(20° − θ) + tan(65° + θ) – cot(25° − θ) is
If x and y are complementary angles, then ______.
