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प्रश्न
Find the value of ‘p’ for which the roots of the following equation are real and equal:
9x2 − 24x + p = 0
योग
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उत्तर
Given:
9x2 − 24x + p = 0
For a quadratic equation ax2 + bx + c = 0, the discriminant is:
D = b2 − 4ac
For real and equal roots, the discriminant must be:
D = 0
Identify the coefficients
a = 9
b = −24
c = p
D = (−24)2 − 4(9) (p)
= 576 − 36p
576 − 36p = 0
36p = 576
`p = 576/36`
p = 16
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Quadratic equations - Exercise 5D [पृष्ठ ७७]
