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Find the value of ‘p’ for which the roots of the following equation are real and equal: 9x2 − 24x + p = 0 - Mathematics

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प्रश्न

Find the value of ‘p’ for which the roots of the following equation are real and equal:

9x2 − 24x + p = 0

योग
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उत्तर

Given:

9x2 − 24x + p = 0

For a quadratic equation ax2 + bx + c = 0, the discriminant is:

D = b2 − 4ac

For real and equal roots, the discriminant must be:

D = 0

Identify the coefficients

a = 9

b = −24

c = p

D = (−24)2 − 4(9) (p)

= 576 − 36p

576 − 36p = 0

36p = 576

`p = 576/36`

p = 16

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अध्याय 5: Quadratic equations - Exercise 5D [पृष्ठ ७७]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic equations
Exercise 5D | Q 6. (ii) | पृष्ठ ७७
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