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Find the separate equation of the following pair of straight lines6(x – 1)2 + 5(x – 1)(y – 2) – 4(y – 3)2 = 0

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प्रश्न

Find the separate equation of the following pair of straight lines
6(x – 1)2 + 5(x – 1)(y – 2) – 4(y – 3)2 = 0

योग
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उत्तर

6(x – 1)2 + 5( x – 1)(y – 2) – 4(y – 3)2 = 0

Let x = x – 1 and y = y – 2

∴ The given equation becomes

6x2 + 5xy – 4y2 = 0

6x2 + 8xy – 3xy – 4y2 = 0

2x(3x + 4y) – Y(3x + 4y) = 0

(2x – y)(3x + 4y) = 0

2x – y = 0 and 3x + 4y = 0

Substituting for x and y, we have

2x – y = 0

⇒ 2(x – 1) – (y – 2) = 0

⇒ 2x – 2 – y + 2 = 0

⇒ 2x – y = 0

3X + 4Y = 0

⇒ 3(x – 1) + 4( y – 2 ) = 0

⇒ 3x – 3 + 4y – 8 = 0

⇒ 3x + 4y – 11 = 0

∴ The separate equations are

2x – y = 0 and 3x + 4y – 11 = 0

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Pair of Straight Lines
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.4 [पृष्ठ २८२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.4 | Q 7. (ii) | पृष्ठ २८२

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