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प्रश्न
Find the refractive index of the liquid if a ray of light strikes surface AB normally and then comes out from face AC at grazing emergence. `(""_aμ_g = 3/2)`

संख्यात्मक
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उत्तर
Given:
Prism is equilateral ⇒ angle A = 60°
Ray is incident normally at face AB ⇒ no deviation
Ray emerges at grazing angle from face AC ⇒ e = 90°
Refractive index of air w.r.t. glass (aμg) = `3/2`
To Find:
Refractive index of the liquid (μ)
Calculation:
At face AC, apply Snell’s law:
μ × sin (60°) = 1 × sin (90°)
`μ xx sqrt3/2 = 1`
μ = `2/sqrt3`
Now convert to absolute refractive index:
`μ_"absolute" = ""_aμ_g xx μ`
= `3/2 xx 2/sqrt3`
= `(3 sqrt3)/4`
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