हिंदी

Find the principal value of the following: sin-1 (12) - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Find the principal value of the following: sin-1 `(1/sqrt(2))`

योग
Advertisements

उत्तर

The principal value branch of sin-1x is `[- pi/2, pi/2]`.

Let sin-1`(1/sqrt(2)) = α, "where" (-pi)/(2) ≤ α ≤ pi/(2)`

∴ sin α = `(1)/(sqrt2) = sin  pi/(4)`

∴ α = `pi/(4)                  ...[∵ - pi/2 ≤ pi/4 ≤ pi/2 ]`

∴ the principal value of sin-1`(1/sqrt(2)) "is" pi/(4)`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Exercise 3.3 [पृष्ठ १०२]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Exercise 3.3 | Q 1.5 | पृष्ठ १०२

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Show that `2sin^-1(3/5) = tan^-1(24/7)`


Show that:

`cos^(-1)(4/5)+cos^(-1)(12/13)=cos^(-1)(33/65)`


Find the domain of `f(x)=cotx+cot^-1x`


Evaluate the following:

`cot^-1  1/sqrt3-\text(cosec)^-1(-2)+sec^-1(2/sqrt3)`


Evaluate: tan `[ 2 tan^-1  (1)/(2) – cot^-1 3]`


In ΔABC, if a = 18, b = 24, c = 30 then find the values of sinA.


In ΔABC prove that `sin  "A"/(2). sin  "B"/(2). sin  "C"/(2) = ["A(ΔABC)"]^2/"abcs"`


Prove the following:

`tan^-1(1/2) + tan^-1(1/3) = pi/(4)`


Prove the following:

`tan^-1["cosθ + sinθ"/"cosθ - sinθ"] = pi/(4) + θ, if θ ∈ (- pi/4, pi/4)`


Find the principal solutions of the following equation:
tan 5θ = -1


Find the principal solutions of the following equation:

cot 2θ = 0.


sin−1x − cos−1x = `pi/6`, then x = ______


The principal value of sin−1`(1/2)` is ______


Evaluate cot(tan−1(2x) + cot−1(2x))


Prove that sin `[tan^-1 ((1 - x^2)/(2x)) + cos^-1 ((1 - x^2)/(1 + x^2))]` = 1


Find the principal value of the following:

`sin^-1 (- 1/2)`


Prove that:

2 tan-1 (x) = `sin^-1 ((2x)/(1 + x^2))`


Show that `sin^-1 (- 3/5) - sin^-1 (- 8/17) = cos^-1 (84/85)`


The value of cot `(tan^-1 2x + cot^-1 2x)` is ______ 


In ΔABC, tan`A/2 = 5/6` and tan`C/2 = 2/5`, then ______


If `sin^-1  3/5 + cos^-1  12/13 = sin^-1 P`, then P is equal to ______ 


If `3sin^-1((2x)/(1 + x^2)) - 4cos^-1((1 - x^2)/(1 + x^2)) + 2tan^-1((2x)/(1 - x^2)) = pi/3`, then x is equal to ______ 


If `tan^-1x + tan^-1y = (4pi)/5`, then `cot^-1x + cot^-1y` equals ______.


`(sin^-1(-1/2) + tan^-1(-1/sqrt(3)))/(sec^-1 (-2/sqrt(3)) + cos^-1(1/sqrt(2))` = ______.


The value of `sin^-1(cos  (53pi)/5)` is ______ 


If 2 tan–1(cos θ) = tan–1(2 cosec θ), then show that θ = π 4, where n is any integer.


`"cos"  2 theta` is not equal to ____________.


If sin-1 x – cos-1 x `= pi/6,` then x = ____________.


`"sin"^-1 (-1/2)`


If tan-1 (x – 1) + tan-1 x + tan-1 (x + 1) = tan-1 3x, then the values of x are ____________.


If `"x" in (- pi/2, pi/2), "then the value of tan"^-1 ("tan x"/4) + "tan"^-1 ((3 "sin" 2 "x")/(5 + 3 "cos" 2 "x"))` is ____________.


`sin[π/3 - sin^-1 (-1/2)]` is equal to:


The equation of the tangent to the curve given by x = a sin3t, y = bcos3t at a point where t = `pi/2` is


If |Z1| = |Z2| and arg (Z1) + arg (Z2) = 0, then


What will be the principal value of `sin^-1(-1/2)`?


What is the principal value of cosec–1(2).


Values of tan–1 – sec–1(–2) is equal to


If f(x) = x5 + 2x – 3, then (f–1)1 (–3) = ______.


Assertion (A): The domain of the function sec–12x is `(-∞, - 1/2] ∪ pi/2, ∞)`

Reason (R): sec–1(–2) = `- pi/4`


Number of values of x satisfying the system of equations `sin^-1sqrt(2 + e^(-2x) - 2e^-x) + sec^-1sqrt(1 - x^2 + x^4) = π/2` and `5^(1+tan^-1x)` = 4 + [cos–1x] is ______ (where [.] denotes greatest integer function)


`cot^-1(sqrt(cos α)) - tan^-1 (sqrt(cos α))` = x, then sin x = ______.


If sin–1a + sin–1b + sin–1c = π, then find the value of `asqrt(1 - a^2) + bsqrt(1 - b^2) + csqrt(1 - c^2)`.


If x ∈ R – {0}, then `tan^-1 ((sqrt(1 + x^2) + sqrt(1 - x^2))/(sqrt(1 + x^2) - sqrt(1 - x^2)))`


The value of cos (2cos–1 x + sin–1 x) at x = `1/5` is ______.


If tan–1 (2x) + tan–1 (3x) = `π/4`, then x = ______.


sin [cot–1 (cos (tan–1 x))] = ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×