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प्रश्न
Find the principal value of the following:
`sec^(-1) (2/sqrt(3))`
योग
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उत्तर
Let `sec^(-1) (2/sqrt(3)) = y`.
Then, `sec y = 2/sqrt(3) = sec (pi/6)`.
We know that the range of the principal value branch of sec−1 is `[0, pi] - {pi/2}` and `sec (pi/6) = 2/sqrt(3)`.
Therefore, the principal value of `sec^(-1) (2/sqrt(3))` is `pi/6`.
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