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Find the principal value of the following: cosec-1(-sqrt2) - Mathematics

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प्रश्न

Find the principal value of the following:

`"cosec"^(-1)(-sqrt2)`

योग
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उत्तर

Let `"cosec"^(-1)(-sqrt2)` = y

Then, cosec y = `-sqrt2 = - "cosec" (pi/4) = "cosec" (-pi/4)`

We know that the range of the principal value branch of cosec−1 is `[-pi/2,pi/2] - {0}`  and `"cosec"(-pi/4) = -sqrt2`.

Therefore, the principal value of `"cosec"^(-1) (-sqrt2)` is `-pi/4`.

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अध्याय 2: Inverse Trigonometric Functions - Exercise 2.1 [पृष्ठ ४२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 2 Inverse Trigonometric Functions
Exercise 2.1 | Q 10 | पृष्ठ ४२

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