Advertisements
Advertisements
प्रश्न
Find the principal value of `sec^-1 (- sqrt(2))`
Advertisements
उत्तर
Let y = `sec^-1 (- sqrt(2))`
Where 0 ≤ y ≤ π
sec y = `- sqrt(2)`
`y +- pi/2`
`1/sec y = - 1/sqrt(2)`
cos y = `- 1/sqrt(2)`
∴ The principal value of `sec^-1 (- sqrt(2)) = (3pi)/4`
APPEARS IN
संबंधित प्रश्न
Show that `2sin^-1(3/5) = tan^-1(24/7)`
Find the principal value of the following:
`sec^(-1) (2/sqrt(3))`
Find the set of values of `cosec^-1(sqrt3/2)`
In ΔABC prove that `(b + c - a) tan "A"/(2) = (c + a - b)tan "B"/(2) = (a + b - c)tan "C"/(2)`.
Prove the following:
`tan^-1(1/2) + tan^-1(1/3) = pi/(4)`
Find the value of `cos^-1 (1/2) + tan^-1 (1/sqrt(3))`
Evaluate `cos[pi/6 + cos^-1 (- sqrt(3)/2)]`
Prove that:
2 tan-1 (x) = `sin^-1 ((2x)/(1 + x^2))`
Find the principal value of `cos^-1 sqrt(3)/2`
In a triangle ABC, ∠C = 90°, then the value of `tan^-1 ("a"/("b + c")) + tan^-1("b"/("c + a"))` is ______.
The equation tan–1x – cot–1x = `(1/sqrt(3))` has ______.
Show that `cos(2tan^-1 1/7) = sin(4tan^-1 1/3)`
If tan-1 3 + tan-1 x = tan-1 8, then x = ____________.
`"cos" ["tan"^-1 {"sin" ("cot"^-1 "x")}]` is equal to ____________.
`"tan"^-1 sqrt3 - "sec"^-1 (-2)` is equal to ____________.
What is the value of `sin^-1(sin (3pi)/4)`?
Values of tan–1 – sec–1(–2) is equal to
What is the values of `cos^-1 (cos (7pi)/6)`
The value of `tan(cos^-1 4/5 + tan^-1 2/3)` is ______.
