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प्रश्न
Find the mean of the following frequency distribution using step-deviation method.
Take assumed mean = 28
| Class Interval | 0 − 8 | 8 − 16 | 16 − 24 | 24 − 32 | 32 − 40 | 40 − 48 |
| Frequency | 10 | 20 | 14 | 16 | 18 | 22 |
योग
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उत्तर
Given: i = class size = 8 and assumed mean (A) = 28
| Class Interval | Frequency (f) | Class mark (x) | d = x − A | t = `(x − A)/i` | ft |
| 0 − 8 | 10 | 4 | −24 | −3 | −30 |
| 8 − 16 | 20 | 12 | −16 | −2 | −40 |
| 16 − 24 | 14 | 20 | −8 | −1 | −14 |
| 24 − 32 | 16 | 28 | 0 | 0 | 0 |
| 32 − 40 | 18 | 36 | 8 | 1 | 18 |
| 40 − 48 | 22 | 44 | 16 | 2 | 44 |
| Total | `sumf = 100` | `sumft= -22` |
By formula,
Mean = `A + (sum ft)/(sumf) xx i`
= `28 + (-22/100) xx 8`
= 28 + 8(−0.22)
= 28 − 1.76
= 26.24
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