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प्रश्न
Find the final temperature of a copper rod. Whose area of cross-section changes from 10 m2 to 11 m2 due to heating. The copper rod is initially kept at 90K. (Coefficient of superficial expansion is 0.0021 /K)
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उत्तर
Given:
Area of copper rod A0 = A1 = 10 m2
Changes of area cross-section ∆A = A2 – A1 = 11 – 10 = 1 m2
Initial temperature t1 = 90 K
∆T = t2 – t1 = t2 – 90
Coefficient of superficial expansion αA = 0.0021 / K Then t2 = ?
| Element | No. of Protons | No. of Neutrons | Mass Number | Stable Isotopes (abundance) | Atomic Mass (amu) |
| 7 | N - 14 (99.6%) | ||||
| 8 | N - 15 (0.4%) | ||||
| Silicon | 14 | 28 | Si - 28 (92.2%) | ||
| 14 | Si - 29 (4.7%) | ||||
| 16 | Si - 30 (3.1%) | ||||
| 17 | CI - 35 (75%) | ||||
| 17 | CI - 37 (25%) |
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