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प्रश्न
Find the equation of the line: containing the origin and having inclination 90°.
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उत्तर
Given, Inclination of line = θ = 90°
∴ the required line is parallel to Y-axis (or lies on the Y-axis.)
Equation of a line parallel to Y-axis is of the form x = h.
Since, the line passes through origin (0, 0).
∴ h = 0
∴ the equation of the required line is x = 0.
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संबंधित प्रश्न
Find the slope of the following lines which pass through the point: (2, – 1), (4, 3)
Find the slope of the following lines which pass through the point: (– 2, 3), (5, 7)
Find the slope of the following lines which pass through the point: (7, 1), (– 3, 1)
If the X and Y-intercepts of line L are 2 and 3 respectively, then find the slope of line L.
Find the slope of the line whose inclination is 45°.
Without using Pythagoras theorem, show that points A (4, 4), B (3, 5) and C (– 1, – 1) are the vertices of a right-angled triangle.
Find the slope of the line which makes angle of 45° with the positive direction of the Y-axis measured clockwise.
Find the slope of the line passing through the following point: (1, 3), (5, 2)
Find the slope of the line passing through the following point: (–1, 3), (3, –1)
Find the slope of the line passing through the following point: (2, – 5), (3, – 1)
Find the slope of the line which makes an angle of 120° with the positive X-axis.
Find the value of k: if the slope of the line passing through the points (3, 4), (5, k) is 9.
Find the value of k: the points (1, 3), (4, 1), (3, k) are collinear.
Find the value of k: the point P(1, k) lies on the line passing through the points A(2, 2) and B(3, 3).
Find the slope of the line y – x + 3 = 0.
Obtain the equation of the line containing the point: (2, 4) and perpendicular to the Y−axis.
Obtain the equation of the line containing the point: (2, 5) and perpendicular to the X−axis.
Find the equation of the line: containing the point T(7, 3) and having inclination 90°.
