Advertisements
Advertisements
प्रश्न
Find the compound interest on ₹ 3200 at 2.5% p.a for 2 years, compounded annually
Advertisements
उत्तर
Principal (P) = ₹ 3200
r = 2.5% p.a
n = 2 years compound annually
∴ Amount (A) = `(1 + "r"/100)^"n"`
= `3200(1 + 25/100)^2`
= 3200 × (1.025)2
= 3362
Compound interest (C.I.) = Amount – Principal
= 3362 – 3200
= 162
APPEARS IN
संबंधित प्रश्न
The interest on a sum of Rs 2000 is being compounded annually at the rate of 4% per annum. Find the period for which the compound interest is Rs 163.20.
The difference between the S.I. and C.I. on a certain sum of money for 2 years at 4% per annum is Rs 20. Find the sum.
The difference between the compound interest and simple interest on a certain sum for 2 years at 7.5% per annum is Rs 360. Find the sum.
On a certain sum of money, lent out at C.I., interests for first, second and third years are Rs. 1,500; Rs. 1,725 and Rs. 2,070 respectively. Find the rate of interest for the (i) second year (ii) third year.
A man borrowed Rs. 20,000 for 2 years at 8% per year compound interest. Calculate :
(i) the interest of the first year.
(ii) the interest of the second year.
(iii) the final amount at the end of the second year.
(iv) the compound interest of two years.
Calculate the difference between the compound interest and the simple interest on ₹ 8,000 in three years and at 10% per annum.
Depreciation value is calculated by the formula, `"P"(1 - "r"/100)^"n"`
A principal becomes ₹ 2028 in 2 years at 4% p.a compound interest. Find the principal
To calculate the growth of a bacteria if the rate of growth is known, the formula for calculation of amount in compound interest can be used.
Find the difference between Compound Interest and Simple Interest on Rs 45,000 at 12% per annum for 5 years.
