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Find the area of the triangle formed by the line joining the vertex of the parabola x2 = 12y to the end points of latus rectum. - Mathematics and Statistics

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प्रश्न

Find the area of the triangle formed by the line joining the vertex of the parabola x2 = 12y to the end points of latus rectum.

योग
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उत्तर


Given equation of the parabola is x2 = 12y.

Comparing this equation with x2 = 4by, we get

4b = 12

∴ b = 3

∴ The co-ordinates of focus are S(0, b), i.e., S(0, 3)

End points of the latus rectum are L(2b, b) and L′(– 2b, b),

i.e., L(6, 3) and L′(– 6, 3)

Also l(LL′) = length of latus rectum

= 4b

= 12

l(OS) = b = 3

Area of the ΔOLL′ = `1/2 xx l("LL"^′) xx l("OS")`

= `1/2 xx 12 xx 3`

∴ Area of the ΔOLL’ = 18 sq. units.

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Conic Sections - Parabola
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Conic Sections - Exercise 7.1 [पृष्ठ १४९]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Exercise 7.1 | Q 11 | पृष्ठ १४९

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