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Find the area of the smaller region bounded by the curves x225+y216 = 1 and x5+y4 = 1, using integration. - Mathematics

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प्रश्न

Find the area of the smaller region bounded by the curves `x^2/25 + y^2/16` = 1 and `x/5 + y/4` = 1, using integration.

योग
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उत्तर

`x^2/25 + y^2/16` = 1 and `x/5 + y/4` = 1

`\implies` y = `4/5 sqrt(25 - x^2)`


The points of intersection of the given curve and line are A(0, 4) and B(5, 0).

Area of shaded region = Area of ellipse in I quadrant – Area of triangle ΔOAB

= `int_0^5 (4/5 sqrt(25 - x^2))dx - 1/2 xx 5 xx 4`

= `4/5 [x/2 sqrt(25 - x^2) + 25/2 sin^-1  x/5]_0^5 - 10  ...[∵ int (sqrt(a^2 - x^2))dx = x/2 sqrt(a^2 - x^2) + a^2/2 sin^-1  x/a]`

= `4/5 [0 + 25/2 sin^-1 1] - 10`

= `10 xx π/2 - 10`

= (5π – 10) sq. units.

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