Advertisements
Advertisements
प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by \[x - \frac{1}{2}\].
Advertisements
उत्तर
Let us denote the given polynomials as
`f(x) = x^3 + 3x^2 + 3x + 1,`
`h(x) = x-1/2`
We will find the remainder when f(x) is divided by h(x).
By the remainder theorem, when (f(x) is divided by h(x) the remainder is
`= f (1/2)`
` = (1/2)^3 + 3 (1/2)^2 + 3 (1/2) + 1`
`= 1/8 + 3/4 + 3/2 + 1`
`= 27 /8`
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`9-12x +X^3`
Identify polynomials in the following:
`f(x)=4x^3-x^2-3x+7`
Give one example each of a binomial of degree 35, and of a monomial of degree 100.
f(x) = 3x4 + 17x3 + 9x2 − 7x − 10; g(x) = x + 5
f(x) = x5 + 3x4 − x3 − 3x2 + 5x + 15, g(x) = x + 3
3x3 − x2 − 3x + 1
2y3 + y2 − 2y − 1
2x4 − 7x3 − 13x2 + 63x − 45
When x3 − 2x2 + ax − b is divided by x2 − 2x − 3, the remainder is x − 6. The values of a and b are respectively
Factorise:
x3 + x2 – 4x – 4
