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Find the Percentage Error in Calculating the Surface Area of a Cubical Box If an Error of 1% is Made in Measuring the Lengths of Edges of the Cube ?

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प्रश्न

Find the percentage error in calculating the surface area of a cubical box if an error of 1% is made in measuring the lengths of edges of the cube ?

योग
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उत्तर

Let x be the edge of the cube and y be the surface area.

\[y = x^2 \]

\[\text { Let } ∆ x \text { be the error in x and } ∆ y \text { be the corresponding error in } y . \]

\[\text { We have }\]

\[\frac{∆ x}{x} \times 100 = 1\]

\[ \Rightarrow 2x = \frac{x}{100} \left[ \text { Let } dx = ∆ x \right]\]

\[\text { Now }, y = x^2 \]

\[ \Rightarrow \frac{dy}{dx} = 2x\]

\[ \therefore ∆ y = \frac{dy}{dx} \times ∆ x = 2x \times \frac{x}{100}\]

\[ \Rightarrow ∆ y = 2\frac{x^2}{100}\]

\[ \Rightarrow ∆ y = 2\frac{y}{100}\]

\[ \Rightarrow \frac{∆ y}{y} = \frac{2}{100}\]

\[ \Rightarrow \frac{∆ y}{y} \times 100 = 2\]

Hence, the percentage error in calculating the surface area is 2.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Differentials, Errors and Approximations - Exercise 14.1 [पृष्ठ ९]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 13 Differentials, Errors and Approximations
Exercise 14.1 | Q 4 | पृष्ठ ९
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