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Find the Differential Equation of the Family of Curves Y = Ae2x + Be−2x, Where a and B Are Arbitrary Constants. - Mathematics

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प्रश्न

Find the differential equation of the family of curves y = Ae2x + Be−2x, where A and B are arbitrary constants.

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उत्तर

The equation of the family of curves is \[y = A e^{2x} + B e^{- 2x}\]                                     ...(1)
where \[A\text{ and }B\] are arbitrary constants.
This equation contains two arbitrary constants, so we shall get a differential equation of second order.
Differentiating equation (1) with respect to x, we get

\[\frac{dy}{dx} = 2A e^{2x} - 2B e^{- 2x}\]                               ...(2)
Differentiating equation (2) with respect to x, we get
\[\frac{d^2 y}{d x^2} = 4A e^{2x} + 4B e^{- 2x} \]
\[ \Rightarrow \frac{d^2 y}{d x^2} = 4\left( A e^{2x} + B e^{- 2x} \right)\]
\[ \Rightarrow \frac{d^2 y}{d x^2} = 4y\]
It is the required differential equation .
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अध्याय 22: Differential Equations - Exercise 22.02 [पृष्ठ १६]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 22 Differential Equations
Exercise 22.02 | Q 4 | पृष्ठ १६

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