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प्रश्न
Find the common difference and write the next four terms of each of the following arithmetic progressions:
`-1, 1/4, 3/2 .....`
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उत्तर
`-1, 1/4, 3/2 .....`
Here, first term (a1) =−1
Common difference (d) = `a_2 - a_1`
`= 1/4 - (-1)`
`=- (1 + 4)/4`
= 5/4
Now, we need to find the next four terms of the given A.P
That is we need to find `a_4, a_5, a_6, a_7`
So using the formula `a_n = a + (n -1)d`
Substituting n = 4, 5, 6, 7 in the above formula
Substituting n = 4, we get
`a_4 = -1 + (4 -1)(5/4)`
`a_4 = -1 + 15/4`
`a_4 = (-4 + 15)/4`
`a_4 = 11/4`
Substituting n = 5, we get
`a_5 = -1 + (5 - 1)(5/4)`
a_5 = - 1 + 5`
`a_5 = 4`
Substituting n = 6, we get
`a_6 = -1 + (6 - 1)(5/4)`
`a_6 = -1 + 25/4`
`a_6 = (-4 + 25)/4`
`a_6 = 21/4`
Substituting n = 7, we get
`a_7 = -1 + (7 -1) (5/4)`
`a_7 = -1 + 30/4`
`a_7 = (-4 + 30)/4`
`a_7 = 26/4`
Therefore, the common difference is `d = 5/4` and the next four term are `11/4 , 4. 21/4 , 26/4`
