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Find co-ordinate of focus, equation of directrix, length of latus rectum and the co-ordinate of end points of latus rectum of the parabola: 3y2 = –16x - Mathematics and Statistics

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प्रश्न

Find co-ordinate of focus, equation of directrix, length of latus rectum and the co-ordinate of end points of latus rectum of the parabola:

3y2 = –16x

योग
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उत्तर

Given equation of the parabola is 3y2 = –16x.

∴ y2 = `-16/3"x"`

Comparing this equation with y2 = – 4ax, we get

4a = `16/3`

∴ a = `4/3`

Co-ordinates of focus are S(–a, 0), i.e., S`(-4/3, 0)`

Equation of the directrix is x – a = 0,

i.e., `"x" - 4/3` = 0 i.e., 3x – 4 = 0

Length of latus rectum = 4a = `4(4/3) = 16/3`

Co-ordinates of end points of latus rectum are (–a, 2a) and (–a, –2a), i.e., `(-4/3, 8/3)` and `(-4/3, -8/3)`.

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Conic Sections - Parabola
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Conic Sections - Exercise 7.1 [पृष्ठ १४९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Exercise 7.1 | Q 1. (v) | पृष्ठ १४९

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