Question

Fill in the blanks:

y = `sinx/(x^2 + 2)`

Differentiating. w.r.t.x.

`("d"y)/("d"x) = (square "d"/("d"x) (sin x) - sin x "d"/("dx) square)/(x^2 + 2)^2`

= `(square  square - sin x  square)/(x^2 + 2)^2`

= `(square - square)/(x^2 + 2)^2`

Answer 1

y = `sinx/(x^2 + 2)`

Differentiating. w.r.t.x., we get

`("d"y)/("d"x) = (x^2+ 2 "d"/("d"x) (sin x) - sin x "d"/("dx) x^2 + 2)/(x^2 + 2)^2`

= `((x^2 + 2)  (cos x) - sin x  (2x))/(x^2 + 2)^2`

= `((x^2 cos x + 2 cos x) - 2x sin x)/(x^2 + 2)^2`