Advertisements
Advertisements
प्रश्न
Figure 1 below shows a metallic rod MN of length l = 80 cm, kept in a uniform magnetic field of flux density B = 0.5 T, on two parallel metallic rails P and Q. Calculate the emf that will be induced between its two ends, when it is moved towards right with a constant velocity v of 36 km/hr.
संख्यात्मक
Advertisements
उत्तर
Given: l = 80 cm
B = 0.5 T
v = 36 km/hr = 10 m/s
Induced emf (e) = Bvl
= 0.5 × 10 × 80 × 10−2
= 4 V
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
