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प्रश्न
Factorize each of the following algebraic expression:
a2 + 14a + 48
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उत्तर
\[\text{ To factorise }a^2 + 14a + 48, \text{ we will find two numbers p and q such that }p + q = 14\text{ and }pq = 48 . \]
Now,
\[8 + 6 = 14 \]
and
\[8 \times 6 = 48\]
\[\text{ Splitting the middle term 14a in the given quadratic as }8a + 6a,\text{ we get: }\]
\[ a^2 + 14a + 48 = a^2 + 8a + 6a + 48\]
\[ = ( a^2 + 8a) + (6a + 48)\]
\[ = a(a + 8) + 6(a + 8)\]
\[ = (a + 6)(a + 8)\]
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The value of p in the equation `(2"p")/3` = 10 is ________
Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
