Advertisements
Advertisements
प्रश्न
f(x) = x4 − 3x2 + 4, g(x) = x − 2
Advertisements
उत्तर
Let us denote the given polynomials as
`f(x) = x^4 - 3x^2 + 4,`
`g(x) = x-2`
We have to find the remainder when f(x) is divided by g(x).
By the remainder theorem, when f(x)is divided by g(x) the remainder is
`f(2) = (2)^4 - 3 (2)^2 + 4`
` = 16 - 12 + 4`
` = 8`
We will calculate remainder by actual division

So the remainder is 8
APPEARS IN
संबंधित प्रश्न
Identify polynomials in the following:
`f(x)=2+3/x+4x`
If `f(x) = 2x^2 - 13x^2 + 17x + 12` find f(2)
f(x) = 4x4 − 3x3 − 2x2 + x − 7, g(x) = x − 1
The polynomials ax3 + 3x2 − 3 and 2x3 − 5x + a when divided by (x − 4) leave the remainders R1 and R2 respectively. Find the values of the following cases, if 2R1 − R2 = 0.
Show that (x − 2), (x + 3) and (x − 4) are factors of x3 − 3x2 − 10x + 24.
x3 − 10x2 − 53x − 42
x3 + 13x2 + 32x + 20
x4 + 10x3 + 35x2 + 50x + 24
2x4 − 7x3 − 13x2 + 63x − 45
If x − 3 is a factor of x2 − ax − 15, then a =
