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Express the following as a single logarithm: 2 log 3 + log 7 + 3 log 5 – 2 - Mathematics

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प्रश्न

Express the following as a single logarithm:

2 log 3 + log 7 + 3 log 5 – 2

योग
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उत्तर

Given: 2 log 3 + log 7 + 3 log 5 – 2

Step-wise calculation:

1. 2 log 3 = log (32) = log 9

2. 3 log 5 = log (53) = log 125

3. –2 = –log 100

4. Combine:

log 9 + log 7 + log 125 – log 100

= log (9 × 7 × 125) – log 100

= `log ((9 xx 7 xx 125)/100)`

5. Compute numerator:

9 × 7 × 125 = 7875

So expression = `log (7875/100)`

6. Simplify the fraction:

`7875/100`

= `(7875 ÷ 25)/(100 ÷ 25)`

= `315/4`

`log (315/4)`, which is equal to log 78.75.

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अध्याय 7: Logarithms - Exercise 7B [पृष्ठ १४६]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 7 Logarithms
Exercise 7B | Q 5. (ii) | पृष्ठ १४६
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