Advertisements
Advertisements
प्रश्न
Express the average rate of the following reaction in terms of all reactants and products.
\[\ce{2A + B -> 3C + 4D}\]
Advertisements
उत्तर
To express the average rate of the reaction
\[\ce{2A + B -> 3C + 4D}\]
In terms of all reactants and products, we divide the change in concentration of each species by its stoichiometric coefficient and the time interval.
Average rate expression is given as
\[\ce{Rate_{avg} = \frac{1}{2} * \frac{\Delta [A]}{\Delta t}}\]
= \[\ce{-\frac{\Delta [B]}{\Delta t}}\]
= \[\ce{\frac{1}{2} * \frac{\Delta [C]}{\Delta t}}\]
= \[\ce{\frac{1}{4} * \frac{\Delta [D]}{\Delta t}}\]
Negative signs for reactants (A and B) because their concentrations decrease. Positive signs for products (C and D) because their concentrations increase. This gives a complete expression of the average rate in terms of all species involved.
