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प्रश्न
Explain the magnetic behaviour of the complex K3[Fe(CN)6] on the basis of valence bond theory.
स्पष्ट कीजिए
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उत्तर
- The magnetic behavior of the complex K3[Fe(CN)6] can be explained based on the strong field nature of the cyanide (CN−) ligands. Fe3+, which has the electron configuration 3d5, undergoes d2sp3 hybridization to form six bonds with the six cyanide ligands in an octahedral arrangement.
- Because the cyanide ions cause a significant separation of the d-orbitals, the five electrons in the Fe3+ ion pair up in the lower-energy t2g orbitals.
- As a result, there are no unpaired electrons in the complex. Since magnetic properties are directly related to the presence of unpaired electrons, the absence of unpaired electrons makes K3[Fe(CN)6] diamagnetic.
- This means the complex does not exhibit any magnetic moment and is not attracted to a magnetic field.
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अध्याय 9: Coordination Compounds - SHORT ANSWER TYPE QUESTIONS [पृष्ठ ५४६]
