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प्रश्न
Explain how sulphur exists in the +4 oxidation state.
स्पष्ट कीजिए
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उत्तर
- Sulphur in the +4 oxidation state occurs when it excites its np-electrons to vacant nd-orbitals (first excited state).
- This gives sulphur four unpaired electrons to form four bonds.
- The hybridisation involved is sp3d.
- The electron distribution is trigonal bipyramidal with one position occupied by a lone pair.
- Such a state is common for sulphur and other heavier group 16 elements due to their vacant d-orbitals.
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अध्याय 7: p-Block Elements - SHORT ANSWER TYPE QUESTIONS [पृष्ठ ४४७]
