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Evaluate: ∫ X . Log X Dx

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प्रश्न

Evaluate: ∫ x . log x dx

योग
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उत्तर

Let ∫ x . log x dx

= ∫ log x . x . dx       ...[by LIATE rule]

Integrating by parts 

I = `"log x" . int  "x"  "dx" - int  ["d"/"dx" ("log x") int  "x"  "dx"] "dx"`

`= "log x" . ("x"^2/2) - int  1/"x" . ("x"^2/2) "dx"`

`= "x"^2/2 . "log x" - 1/2 int  "x"  "dx"`

`= "x"^2/2 . "log x" - 1/2 ("x"^2/2) + "c"`

`= "x"^2/2 . "log x" - "x"^2/4" + c`

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