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Evaluate the following: dee∫02dxex+e-x - Mathematics

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प्रश्न

Evaluate the following:

`int_0^2 ("d"x)/("e"^x + "e"^-x)`

योग
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उत्तर

Let I = `int_0^2 ("d"x)/("e"^x + "e"^-x)`

= `int_0^1 ("d"x)/("e"^x + 1/"e"^x)`

= `int_0^1 ("d"x)/(("e"^(2x) + 1)/"e"^x)`

= `int_0^1 ("e"^x "d"x)/("e"^(2x) + 1)`

Put ex = t

⇒ ex dx = dt

Changing the limit, we have

When x = 0

∴ t = e0 = 1

When x = 1

∴ I = `int_1^"e" "dt"/("t"^2 + 1)`

= `[tan^-1 "t"]_1^"e"`

= `[tan^-1 "e" - tan^-1 (1)]`

= `tan^-1 "e" - pi/4`

Hence, I = `tan^-1 "e" - pi/4`.

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अध्याय 7: Integrals - Exercise [पृष्ठ १६५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 7 Integrals
Exercise | Q 29 | पृष्ठ १६५

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