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प्रश्न
Evaluate `sin^-1 (sin (3π)/4) + cos^-1 (cos π) + tan^-1 (1)`.
योग
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उत्तर
`sin^-1 (sin (3π)/4) + cos^-1 (cos π) + tan^-1 (1)`
= `sin^-1 [sin(π - π/4)] + π + tan^-1 (tan π/4)`
= `π/4 + π + π/4`
= `π/2 + π`
= `(3π)/2`
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