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Evaluate ππsin-1(sin 3π4)+cos-1(cosπ)+tan-1(1). - Mathematics

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प्रश्न

Evaluate `sin^-1 (sin  (3π)/4) + cos^-1 (cos π) + tan^-1 (1)`.

योग
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उत्तर

`sin^-1 (sin  (3π)/4) + cos^-1 (cos π) + tan^-1 (1)`

= `sin^-1 [sin(π - π/4)] + π + tan^-1 (tan  π/4)`

= `π/4 + π + π/4`

= `π/2 + π`

= `(3π)/2`

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2022-2023 (March) Outside Delhi Set 1

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