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प्रश्न
Evaluate `int_0^1 (x(sin^-1 x)^2)/sqrt(1 - x^2)` dx
योग
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उत्तर
Let I = `int_0^1 (x(sin^-1 x)^2)/sqrt(1 - x^2)` dx
Put sin-1 x = t `therefore` x = sin t
`1/(sqrt(1 - x^2)` dx = dt
when x = 0, t = o
x = 1, t = `π/2`
I = `int_0^(π//2)` t2 sin t dt
Integrating by parts, we get
I = `[t^2 (-cos t)_0^(π//2) - int_0^(π//2)` 2t(-cos t) dt
I = `[(-π^2)/4 cos π/2] - [0] + int_0^(π//2)` 2t cos t dt
I = `int_0^(π//2)` 2t. cos t dt
Integrating by parts, we get
I = `[2t sin]_0^(π//2) - int_0^(π//2)` 2 sin t dt
I = `[2. π/2. sin π/2] - [0] - [-2 cos t]_0^(π//2)`
I = π + 2 `[cos π/2 - cos 0]`
I = π - 2
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