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प्रश्न
Evaluate the following integrals : `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))*dx`
Evaluate: `∫_2^7 sqrtx/(sqrtx + sqrt(9 − x))dx`
मूल्यांकन
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उत्तर
Let I = `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x)) . dx` ...[i]
= `int_2^7 sqrt(2 + 7 - x)/(sqrt(2 + 7 - x) + sqrt(9 - (2 + 7 - x))) . dx ...[∵ int_"a"^"b" f(x) . dx = int_"a"^"b" f("a" + "b" - x) . dx]`
∴ I = `int_2^7 sqrt(9 - x)/(sqrt(9 - x) + sqrt(x))*dx` ...[ii]
Adding [i] and [ii], we get
2I = `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x)) . dx + int_2^7 sqrt(9 - x)/(sqrt(9 - x) + sqrt(x)) . dx`
= `int_2^7 (sqrt(x) + sqrt(9 - x))/(sqrt(x) + sqrt(9 - x))*dx`
= `int_2^7 1 . dx`
= `[x]_2^7`
∴ 2I = 7 – 2 = 5
∴ I = `(5)/(2)`
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