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Evaluate: ∫_2^7 sqrtx/(sqrtx + sqrt(9 − x))dx - Mathematics and Statistics

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प्रश्न

Evaluate the following integrals : `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))*dx`

Evaluate: `∫_2^7 sqrtx/(sqrtx + sqrt(9 − x))dx`

मूल्यांकन
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उत्तर

Let I = `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))  .  dx`         ...[i]

= `int_2^7 sqrt(2 + 7 - x)/(sqrt(2 + 7 - x) + sqrt(9 - (2 + 7 - x)))  .  dx            ...[∵ int_"a"^"b" f(x) .  dx = int_"a"^"b" f("a" + "b" - x)  .  dx]`

∴ I = `int_2^7 sqrt(9 - x)/(sqrt(9 - x) + sqrt(x))*dx`      ...[ii]

Adding [i] and [ii], we get

2I = `int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))  .  dx + int_2^7 sqrt(9 - x)/(sqrt(9 - x) + sqrt(x))  .  dx` 

= `int_2^7 (sqrt(x) + sqrt(9 - x))/(sqrt(x) + sqrt(9 - x))*dx`

= `int_2^7 1  .  dx`

= `[x]_2^7`

∴ 2I = 7 – 2 = 5

∴ I = `(5)/(2)`

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अध्याय 6: Definite Integration - EXERCISE 6.2 [पृष्ठ १४८]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 6 Definite Integration
EXERCISE 6.2 | Q 6) | पृष्ठ १४८
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